{"id":18394,"date":"2024-04-19T07:26:49","date_gmt":"2024-04-19T07:26:49","guid":{"rendered":"https:\/\/soicau3102.minhngocxoso.com\/?p=18394"},"modified":"2024-04-19T07:26:49","modified_gmt":"2024-04-19T07:26:49","slug":"cach-soi-va-bat-tong-de-hang-ngay-nam-2024","status":"publish","type":"post","link":"https:\/\/soicauvip6h30.com\/cach-soi-va-bat-tong-de-hang-ngay-nam-2024\/","title":{"rendered":"C\u00e1ch soi v\u00e0 b\u1eaft t\u1ed5ng \u0111\u1ec1 h\u00e0ng ng\u00e0y n\u0103m 2024"},"content":{"rendered":"
Sau khi \u0111\u00e3 bi\u1ebft r\u00f5 c\u00e1ch ph\u00e2n lo\u1ea1i t\u1ed5ng \u0111\u1ec1. Anh em c\u1ea7n bi\u1ebft c\u00e1ch soi t\u1ed5ng \u0111\u1ec1 nh\u01b0 th\u1ebf n\u00e0o. T\u00f9y theo t\u1ed5ng c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t h\u00e0ng ng\u00e0y l\u00e0 t\u1ed5ng m\u1ea5y m\u00e0 c\u00f3 c\u00e1ch soi c\u1ea7u l\u00f4 th\u00edch h\u1ee3p cho ng\u00e0y h\u00f4m sau. Th\u00f4ng th\u01b0\u1eddng c\u00e1c tay ch\u01a1i l\u00f4 \u0111\u1ec1 l\u00e2u n\u0103m s\u1ebd \u00e1p d\u1ee5ng b\u00f3ng \u00e2m, b\u00f3ng d\u01b0\u01a1ng l\u00f4 \u0111\u1ec1 \u0111\u1ec3 t\u00ednh.<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 0 h\u00f4m sau v\u1ec1 t\u1ed5ng m\u1ea5y? => \u0111\u00e1nh t\u1ed5ng 5<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 1 h\u00f4m sau v\u1ec1 t\u1ed5ng m\u1ea5y? => \u0111\u00e1nh t\u1ed5ng 6<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 2 h\u00f4m sau v\u1ec1 t\u1ed5ng m\u1ea5y? => \u0111\u00e1nh t\u1ed5ng 7<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 3 h\u00f4m sau v\u1ec1 t\u1ed5ng m\u1ea5y? => \u0111\u00e1nh t\u1ed5ng 8<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 4 h\u00f4m sau ra t\u1ed5ng m\u1ea5y? => \u0111\u00e1nh t\u1ed5ng 9<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 5 h\u00f4m sau \u0111\u00e1nh con g\u00ec? => \u0111\u00e1nh t\u1ed5ng 1<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 6 h\u00f4m sau \u0111\u00e1nh con g\u00ec? => \u0111\u00e1nh t\u1ed5ng 3<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 7 h\u00f4m sau v\u1ec1 t\u1ed5ng m\u1ea5y? => \u0111\u00e1nh t\u1ed5ng 0<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 8 h\u00f4m sau \u0111\u00e1nh con g\u00ec? => \u0111\u00e1nh t\u1ed5ng 5<\/p>\n
\u0110\u1ec1 v\u1ec1 t\u1ed5ng 9 h\u00f4m sau \u0111\u00e1nh con g\u00ec? => \u0111\u00e1nh t\u1ed5ng 2<\/p>\n
D\u00f9ng 5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 5 s\u1ed1 gi\u1ea3i nh\u1ea5t gh\u00e9p l\u1ea1i v\u1edbi nhau t\u1ea1o th\u00e0nh 1 s\u1ed1. Sau \u0111\u00f3 c\u1ed9ng l\u1ea1i c\u00e1c s\u1ed1 n\u00e0y v\u1edbi nhau theo quy lu\u1eadt Pascal. C\u00f4ng ki\u1ec3u 3 s\u1ed1 li\u00ean ti\u1ebfp v\u1edbi nhau cho t\u1edbi khi ch\u1ec9 c\u00f2n 2 s\u1ed1. D\u00f9ng 2 s\u1ed1 n\u00e0y \u0111\u1ec3 nu\u00f4i l\u00f4 trong t\u1ed1i \u0111a 3 ng\u00e0y.<\/p>\n
V\u00ed d\u1ee5: ng\u00e0y 20\/1\/2024 c\u00f3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 45271 v\u00e0 gi\u1ea3i nh\u1ea5t l\u00e0 23604. Gh\u00e9p l\u1ea1i v\u1edbi nhau th\u00e0nh 1 con s\u1ed1 4527123604. C\u1ed9ng 3 s\u1ed1 li\u00ean ti\u1ebfp theo lu\u1eadt Pascal nh\u01b0 sau:<\/p>\n
4527123604<\/p>\n
979835964<\/p>\n
66718450<\/p>\n
2389295<\/p>\n
518114<\/p>\n
69925<\/p>\n
5817<\/p>\n
398<\/p>\n
27<\/p>\n
Ta d\u00f9ng con 27 \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo. K\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y 21\/1\/2024 n\u1ed5 l\u00f4 27.<\/p>\n
<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u gi\u1ea3i \u0111\u1eb7c bi\u1ec7t theo t\u1ed5ng n\u00e0y c\u0169ng d\u1ef1a v\u00e0o c\u00f4ng th\u1ee9c to\u00e1n h\u1ecdc. Sau h\u00e0ng ng\u00e0n l\u1ea7n th\u1eed nghi\u1ec7m th\u00ec Kubet \u0111\u00e3 r\u00fat ra 1 c\u00f4ng th\u1ee9c b\u1eaft t\u1ed5ng \u0111\u1ec1 m\u00e0 kh\u00f4ng c\u00f3 n\u01a1i n\u00e0o c\u00f3. C\u00e1ch n\u00e0y s\u1ebd l\u1ea5y 2 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a 2 ng\u00e0y li\u00ean ti\u1ebfp nhau \u0111\u1ec3 t\u00ednh. C\u00f4ng th\u1ee9c nh\u01b0 sau:<\/p>\n
C\u1ed9ng t\u1ea5t c\u1ea3 con s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 nh\u1ea5t ta \u0111\u01b0\u1ee3c 1 con s\u1ed1 l\u00e0 AB.<\/p>\n
C\u1ed9ng t\u1ea5t c\u1ea3 con s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 nh\u1ea5t ta \u0111\u01b0\u1ee3c 1 con s\u1ed1 l\u00e0 CD.<\/p>\n
Ta l\u1ea5y A + B = E; C + D = F. Nh\u01b0 v\u1eady ta c\u00f3 c\u1eb7p s\u1ed1 E v\u00e0 F.<\/p>\n
Sau khi \u0111\u00e3 ho\u00e0n th\u00e0nh c\u00e1c b\u01b0\u1edbc tr\u00ean, ta l\u1ea1i x\u00e9t ti\u1ebfp c\u00e1c tr\u01b0\u1eddng h\u1ee3p sau<\/p>\n
N\u1ebfu E < 10 v\u00e0 F < 10 th\u00ec l\u1ea5y 10 \u2013 E = G v\u00e0 10 \u2013 F = H. Ta c\u00f3 l\u00f4 GH, HG \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo.<\/p>\n
N\u1ebfu E < 10 v\u00e0 F > 10 th\u00ec l\u1ea5y 10 \u2013 E = G v\u00e0 20 \u2013 F = K. Ta c\u00f3 l\u00f4 GK, KG \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo.<\/p>\n
N\u1ebfu E > 10 v\u00e0 F < 10 th\u00ec l\u1ea5y 20 \u2013 E = T v\u00e0 10 \u2013 F = H. Ta c\u00f3 l\u00f4 TH, HT \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo.<\/p>\n
N\u1ebfu E > 10 v\u00e0 F > 10 th\u00ec l\u1ea5y 20 \u2013 E = T v\u00e0 20 \u2013 F = K. Ta c\u00f3 l\u00f4 TK, KT \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y mai.<\/p>\n
N\u1ebfu tr\u01b0\u1eddng h\u1ee3p E, F \u0111\u1ec1u l\u00e0 0 th\u00ec \u0111\u00e1nh l\u00f4 k\u00e9p 00 cho ng\u00e0y h\u00f4m sau.<\/p>\n
M\u00ecnh khuy\u00ean anh em n\u00ean nu\u00f4i c\u00e1c c\u1eb7p l\u00f4 m\u00e0 m\u00ecnh \u0111\u00e3 t\u00ednh to\u00e1n \u1edf tr\u00ean t\u1ed1i \u0111a 3 ng\u00e0y. V\u00ec v\u1eady c\u1ea7n chu\u1ea9n b\u1ecb v\u1ed1n tr\u01b0\u1edbc khi \u00e1p d\u1ee5ng c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 n\u00e0y nha. N\u1ebfu tr\u00fang l\u00f4 th\u00ec d\u1eebng kho\u1ea3n v\u00e0i ng\u00e0y r\u1ed3i t\u00ednh to\u00e1n lo\u1ea1i t\u1eeb \u0111\u1ea7u, sau \u0111\u00f3 h\u00e3y nu\u00f4i l\u00f4 kh\u00e1c ti\u1ebfp. C\u00f2n n\u1ebfu sau 3 ng\u00e0y kh\u00f4ng tr\u00fang th\u00ec th\u00ec d\u1eebng 3 ng\u00e0y sau h\u00e3y \u0111\u00e1nh ti\u1ebfp.<\/p>\n
Tr\u00ean \u0111\u00e2y m\u00ecnh \u0111\u00e3 h\u01b0\u1edbng d\u1eabn chi ti\u1ebft c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 h\u00e0ng ng\u00e0y. Hy v\u1ecdng anh em \u0111\u1ecdc th\u1eadt k\u1ef9 c\u00f4ng th\u1ee9c v\u00e0 r\u00fat ra \u0111\u01b0\u1ee3c ph\u01b0\u01a1ng ph\u00e1p b\u1eaft t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ri\u00eang cho m\u00ecnh. Ngo\u00e0i ra, c\u00e1ch n\u00e0y c\u0169ng c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng v\u1edbi b\u1ea1c nh\u1edb l\u00f4 \u0111\u1ec1 r\u1ea5t hi\u1ec7u qu\u1ea3. Ch\u00fac anh em may m\u1eafn.<\/p>\n