{"id":18421,"date":"2024-04-19T10:11:02","date_gmt":"2024-04-19T10:11:02","guid":{"rendered":"https:\/\/soicau3102.minhngocxoso.com\/?p=18421"},"modified":"2024-04-19T10:11:02","modified_gmt":"2024-04-19T10:11:02","slug":"cach-vao-tien-nuoi-bach-thu-lo-khung-5-ngay","status":"publish","type":"post","link":"https:\/\/soicauvip6h30.com\/cach-vao-tien-nuoi-bach-thu-lo-khung-5-ngay\/","title":{"rendered":"C\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i b\u1ea1ch th\u1ee7 l\u00f4 khung 5 ng\u00e0y"},"content":{"rendered":"
Nu\u00f4i l\u00f4 c\u1eb7p trong 3 ng\u00e0y hay nu\u00f4i l\u00f4 song th\u1ee7 th\u00ec ch\u1eafc l\u00e0 anh em n\u00e0o c\u0169ng bi\u1ebft r\u1ed3i \u0111\u00fang kh\u00f4ng n\u00e0o, ch\u00fang ta ch\u1ec9 c\u1ea7n mang c\u1eb7p s\u1ed1 \u0111i ch\u01a1i trong 3 ng\u00e0y l\u00e0 \u0111\u01b0\u1ee3c, tuy nhi\u00ean c\u00f3 nhi\u1ec1u b\u1ea1n b\u1ea3o ch\u01a1i 3 ng\u00e0y th\u00ec l\u1ed7 l\u1edbn, xin th\u01b0a v\u1edbi c\u00e1c b\u1ea1n kh\u00f4ng h\u1ec1 c\u00f3 chuy\u1ec7n \u0111\u00f3 n\u1ebfu nh\u01b0 c\u00e1c b\u1ea1n bi\u1ebft c\u00e1ch t\u00ednh to\u00e1n v\u00e0o ti\u1ec1n nh\u00e9. H\u00f4m nay nu\u00f4i l\u00f4 s\u1ebd h\u01b0\u1edbng d\u1eabn c\u00e1c b\u1ea1n c\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 c\u1eb7p khung 3 ng\u00e0y theo t\u1ec9 l\u1ec7 1:3;10 \u0111\u1ec3 ch\u00fang ta s\u1ebd l\u1eddi m\u1ed9t s\u1ed1 ti\u1ec1n nh\u1ea5t \u0111\u1ecbnh cho d\u00f9 l\u00f4 c\u00f3 ra \u1edf b\u1ea5t k\u1ef3 ng\u00e0y nu\u00f4i n\u00e0o nh\u00e9.<\/p>\n
\u1ede \u0111\u00e2y m\u00ecnh nu\u00f4i theo t\u1ec9 l\u1ec7 1:3:10 v\u00e0 \u00e1p d\u1ee5ng tr\u01b0\u1eddng h\u1ee3p l\u00f4 v\u1ec1 1 nh\u00e1y v\u00e0 l\u00f4 ch\u01a1i 23.000 vn\u0111 \u0103n 80.000 vn\u0111 nh\u00e9 c\u00e1c b\u1ea1n, n\u1ebfu nh\u01b0 tr\u01b0\u1eddng h\u1ee3p l\u00f4 v\u1ec1 2 nh\u00e1y ho\u1eb7c nh\u00e0 c\u00e1i cho ch\u00fang ta \u0103n cao h\u01a1n th\u00ec ch\u00fang ta s\u1ebd \u0103n \u0111\u01b0\u1ee3c d\u00e0y h\u01a1n nh\u00e9, b\u00e2y gi\u1edd ch\u00fang ta s\u1ebd xem ch\u01a1i nh\u01b0 th\u1ebf n\u00e0y th\u00ec m\u1ed9t ng\u00e0y l\u1eddi \u0111\u01b0\u1ee3c bao nhi\u00eau ti\u1ec1n nh\u00e9.<\/p>\n
Ng\u00e0y 1<\/b> : \u0111\u00e1nh 10 \u0111i\u1ec3m m\u1ed7i con (2 con l\u00e0 20 \u0111i\u1ec3m) (460.000 vn\u0111) n\u1ebfu \u0103n l\u1eddi 80.000 vn\u0111 x 10 = 800.000 vn\u0111 \u2013 460.000 vn\u0111 = 340.000 vn\u0111. Tr\u01b0\u1eddng h\u1ee3p ng\u00e0y \u0111\u1ea7u nu\u00f4i kh\u00f4ng v\u1ec1 th\u00ec ch\u00fang ta s\u1ebd nu\u00f4i ti\u1ebfp \u1edf ng\u00e0y th\u1ee9 hai nh\u01b0 sau.<\/p>\n
Ng\u00e0y 2<\/b> : \u0111\u00e1nh m\u1ed7i con 30 \u0111i\u1ec3m (1.380.000 vn\u0111) n\u1ebfu \u0103n s\u1ebd l\u1eddi 30\u00d780.000 vn\u0111 = 2.400.000 vn\u0111 \u2013 1.380.000 vn\u0111 = 1.020.000 vn\u0111, trong 2 ng\u00e0y ch\u00fang ta l\u1eddi nh\u01b0 sau 1.020.000 vn\u0111 \u2013 460.000 vn\u0111 = 560.000 vn\u0111, nh\u01b0 v\u1eady m\u1ed7i ng\u00e0y \u0103n \u0111\u01b0\u1ee3c g\u1ea7n 300.000 vn\u0111. N\u1ebfu nh\u01b0 ng\u00e0y nu\u00f4i th\u1ee9 hai kh\u00f4ng ra ch\u00fang ta chuy\u1ec3n sang nu\u00f4i ng\u00e0y cu\u1ed1i.<\/p>\n
Ng\u00e0y 3<\/b> : \u0111\u00e1nh m\u1ed7i con 100 \u0111i\u1ec3m (4.600.000 vn\u0111) n\u1ebfu \u0103n s\u1ebd l\u1eddi 8.000.000 vn\u0111 \u2013 4.600.000 vn\u0111 = 3.400.000 vn\u0111, trong 3 ng\u00e0y nu\u00f4i ch\u00fang ta s\u1ebd l\u1eddi 3.400.000 vn\u0111 \u2013 1.380.000 vn\u0111 \u2013 460.000 vn\u0111 = 1.560.000 vn\u0111, nh\u01b0 v\u1eady trong 3 ng\u00e0y ch\u00fang ta \u0103n m\u1ed7i ng\u00e0y l\u00e0 h\u01a1n 500.000 vn\u0111, n\u1ebfu khung nu\u00f4i n\u00e0o c\u0169ng \u0103n ng\u00e0y th\u1ee9 ba th\u00ec m\u1ed7i th\u00e1ng ch\u00fang ta c\u0169ng c\u00f3 \u0111\u01b0\u1ee3c 15.000.000 vn\u0111 r\u1ed3i.<\/p>\n
Tr\u00ean \u0111\u00e2y l\u00e0 m\u1ed9t c\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 c\u1eb7p khung 3 ng\u00e0y<\/i><\/b> theo t\u1ec9 l\u1ec7 m\u00e0 ch\u00fang t\u00f4i \u0111\u01b0a ra cho c\u00e1c b\u1ea1n tham kh\u1ea3o, c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 t\u00ednh to\u00e1n theo m\u1ed9t t\u1ec9 l\u1ec7 kh\u00e1c c\u00f3 th\u1ec3 v\u00e0o ti\u1ec1n nhi\u1ec1u h\u01a1n ho\u1eb7c \u00edt h\u01a1n m\u00e0 l\u00e0m sao m\u00e0 m\u1ed7i ng\u00e0y l\u00f4 t\u00f4 nu\u00f4i ra ch\u00fang ta \u0111\u1ec1u \u0103n \u0111\u01b0\u1ee3c m\u1ed9t s\u1ed1 ti\u1ec1n \u0111\u00e3 t\u00ednh to\u00e1n ra t\u1eeb tr\u01b0\u1edbc r\u1ed3i, ch\u00fac c\u00e1c b\u1ea1n may m\u1eafn.<\/p>\nC\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i b\u1ea1ch th\u1ee7 l\u00f4 khung 5 ng\u00e0y<\/h2>\n
Nu\u00f4i l\u00f4 b\u1ea1ch th\u1ee7 khung 5 ng\u00e0y l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p t\u00ednh to\u00e1n ch\u01a1i an to\u00e0n l\u00e2u d\u00e0i \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi tin d\u00f9ng tr\u00ean trang ch\u1ee7 nu\u00f4i l\u00f4 b\u1edfi v\u00ec n\u00f3 s\u1ebd hi\u1ec7u qu\u1ea3 g\u1ea5p nhi\u1ec1u l\u1ea7n so v\u1edbi ch\u01a1i theo t\u1eebng ng\u00e0y, c\u00e1ch ch\u01a1i n\u00e0y n\u1ebfu ch\u00fang ta bi\u1ebft c\u00e1ch soi c\u1ea7u v\u00e0 bi\u1ebft c\u00e1ch chia t\u1ec9 l\u1ec7 ti\u1ec1n ch\u01a1i theo t\u1eebng ng\u00e0y th\u00ec r\u1ea5t l\u00e0 hi\u1ec7u qu\u1ea3. H\u00f4m nay ch\u00fang t\u00f4i s\u1ebd chia s\u1ebb cho c\u00e1c b\u1ea1n c\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 b\u1ea1ch th\u1ee7 khung 5 ng\u00e0y \u0111\u1ec3 c\u00e1c b\u1ea1n \u00e1p d\u1ee5ng v\u00e0o nu\u00f4i nh\u00e9.<\/p>\n
<\/p>\n
\u1ede \u0111\u00e2y ch\u00fang t\u00f4i s\u1ebd \u00e1p d\u1ee5ng tr\u01b0\u1eddng h\u1ee3p l\u00f4 nu\u00f4i ch\u1ec9 v\u1ec1 1 nh\u00e1y v\u00e0 m\u1ed9t ng\u00e0y ch\u00fang t\u00f4i t\u00ednh s\u1ebd l\u1eddi 300.000 vn\u0111 v\u00e0 \u00e1p d\u1ee5ng v\u1edbi s\u1ed1 ti\u1ec1n \u0111\u00e1nh 23.000 vn\u0111 1 \u0111i\u1ec3m l\u00f4 v\u00e0 \u0103n th\u00ec \u0111\u01b0\u1ee3c 80.000 vn\u0111 nh\u00e9, \u1edf nh\u1eefng n\u01a1i kh\u00e1c \u0103n cao h\u01a1n th\u00ec ch\u1eafc ch\u1eafn ch\u00fang ta s\u1ebd l\u1eddi nhi\u1ec1u h\u01a1n.<\/p>\n
Ng\u00e0y 1<\/b> : \u0111\u00e1nh 6 \u0111i\u1ec3m (6 x 23.000 vn\u0111 = 138.000 vn\u0111) n\u1ebfu \u0103n l\u1eddi 80.000 vn\u0111 x 6 = 480.000 vn\u0111 \u2013 138.000 vn\u0111 = 342.000 vn\u0111.<\/p>\n
Ng\u00e0y 2<\/b> : \u0111\u00e1nh 13 \u0111i\u1ec3m (13 x 23.000 vn\u0111 = 299.000 vn\u0111) n\u1ebfu \u0103n l\u1eddi 80.000 vn\u0111 x 13 = 1.040.000 vn\u0111 \u2013 299.000 vn\u0111 = 741.000 vn\u0111.<\/p>\n
Ng\u00e0y 3<\/b> : \u0111\u00e1nh 25 \u0111i\u1ec3m (25 x 23.000 vn\u0111 = 575.000 vn\u0111) n\u1ebfu \u0103n l\u1eddi 80.000 vn\u0111 x 25 = 2.000.000 vn\u0111 \u2013 575.000 vn\u0111 = 1.425.000 vn\u0111.<\/p>\n
Ng\u00e0y 4<\/b> : \u0111\u00e1nh 40 \u0111i\u1ec3m (23.000 vn\u0111 x 40 = 920.000 vn\u0111) n\u1ebfu \u0103n l\u1eddi 80.000 vn\u0111 x 40 = 3.200.000 vn\u0111 \u2013 920.000 vn\u0111 = 2.280.000 vn\u0111.<\/p>\n
Ng\u00e0y 5<\/b> : \u0111\u00e1nh 61 \u0111i\u1ec3m (23.000 vn\u0111 x 61 = 1.403.000 vn\u0111) n\u1ebfu \u0103n l\u1eddi 80.000 vn\u0111 x 61 = 8.880.000 vn\u0111 \u2013 1.403.000 vn\u0111 = 3.477.000 vn\u0111.<\/p>\n
Theo c\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i l\u00f4 b\u1ea1ch th\u1ee7 khung 5 ng\u00e0y<\/i><\/b> \u1edf tr\u00ean \u0111\u00e2y th\u00ec m\u1ed7i ng\u00e0y ch\u00fang ta s\u1ebd l\u1eddi \u0111\u01b0\u1ee3c 300.000 vn\u0111 b\u1ea5t k\u1ec3 l\u00f4 nu\u00f4i v\u1ec1 \u1edf ng\u00e0y n\u00e0o. S\u1ed1 ti\u1ec1n m\u00e0 ch\u00fang ta c\u1ea7n chu\u1ea9n b\u1ecb \u0111\u1ec3 nu\u00f4i theo c\u00e1ch n\u00e0y t\u1ed5ng c\u1ed9ng l\u00e0 138.000 vn\u0111 + 299.000 vn\u0111 + 575.000 vn\u0111 + 920.000 vn\u0111 + 1.403.000 vn\u0111 = 3.335.000 vn\u0111.<\/p>\n
N\u1ebfu c\u00e1ch ch\u01a1i theo t\u1ec9 l\u1ec7 n\u00e0y m\u00e0 chu k\u1ef3 n\u00e0o c\u0169ng \u0103n th\u00ec m\u1ed7i th\u00e1ng ch\u00fang ta s\u1ebd c\u00f3 trong tay t\u1ea7m kho\u1ea3ng 9.000.000 vn\u0111. C\u00e1c b\u1ea1n c\u0169ng c\u00f3 th\u1ec3 t\u0103ng s\u1ed1 ti\u1ec1n l\u1eddi c\u1ee7a m\u00ecnh l\u00ean b\u1eb1ng c\u00e1ch t\u0103ng th\u00eam ti\u1ec1n \u0111\u1ec3 ch\u01a1i nu\u00f4i m\u1ed7i ng\u00e0y nh\u00e9. Ch\u00fac c\u00e1c b\u1ea1n may m\u1eafn !<\/p>\n
H\u00f4m nay s\u1ebd chia s\u1ebb cho c\u00e1c b\u1ea1n c\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i d\u00e0n \u0111\u1ec1 36 s\u1ed1 khung 3 ng\u00e0y d\u00e0nh cho nh\u1eefng b\u1ea1n ch\u01b0a bi\u1ebft v\u00e0 nh\u1eefng b\u1ea1n th\u00edch ch\u01a1i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t tham kh\u1ea3o c\u00e1ch \u0111\u1ea7u t\u01b0 v\u1ed1n \u0111\u1ec3 nu\u00f4i m\u1ed7i ng\u00e0y nh\u00e9.<\/p>\n
\u1ede \u0111\u00e2y m\u00ecnh s\u1ebd \u00e1p d\u1ee5ng ch\u01a1i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1edbi gi\u1ea3i th\u01b0\u1edfng 1 ngh\u00ecn \u0103n 70 ngh\u00ecn nh\u00e9 c\u00e1c b\u1ea1n, \u1edf c\u00e1c nh\u00e0 c\u00e1i kh\u00e1c t\u1ec9 l\u1ec7 \u0103n cao h\u01a1n th\u00ec c\u00e1c b\u1ea1n s\u1ebd l\u1eddi \u0111\u01b0\u1ee3c nhi\u1ec1u h\u01a1n nh\u00e9.<\/p>\n
Ng\u00e0y 1<\/b> : \u0111\u00e1nh m\u1ed7i con 10 ngh\u00ecn (10.000 vn\u0111 x 36 = 360.000 vn\u0111), n\u1ebfu \u0103n l\u1eddi 10 x 70.000 = 700.000 vn\u0111 \u2013 360.000 vn\u0111 = 340.000 vn\u0111.<\/p>\n
Ng\u00e0y 2<\/b> : \u0111\u00e1nh m\u1ed7i con 30 ngh\u00ecn (30.000 vn\u0111 x 36 = 1.080.000 vn\u0111) n\u1ebfu \u0103n l\u1eddi 30 x 70.000 vn\u0111 = 2.100.000 vn\u0111 \u2013 1.080.000 vn\u0111 = 1.020.000 vn\u0111.<\/p>\n
Ng\u00e0y 3<\/b> : \u0111\u00e1nh m\u1ed7i con 70 ngh\u00ecn (70.000 vn\u0111 x 36 = 2.520.000 vn\u0111, n\u1ebfu \u0103n l\u1eddi 70 x 70.000 vn\u0111 = 4.900.000 vn\u0111 \u2013 2.520.000 vn\u0111 = 2.380.000 vn\u0111.<\/p>\n
Theo c\u00e1ch v\u00e0o ti\u1ec1n nu\u00f4i d\u00e0n \u0111\u1ec1 36 s\u1ed1 khung 3 ng\u00e0y<\/i><\/b> \u1edf b\u00ean tr\u00ean \u0111\u00e2y th\u00ec t\u00ednh ra m\u1ed7i ng\u00e0y ch\u00fang ta s\u1ebd l\u1eddi \u0111\u01b0\u1ee3c 300.000 vn\u0111, nh\u01b0 v\u1eady trong 3 ng\u00e0y ch\u00fang ta s\u1ebd l\u1eddi \u0111\u01b0\u1ee3c t\u1ea7m 900.000 vn\u0111 cho d\u00f9 \u0103n \u1edf b\u1ea5t k\u1ef3 ng\u00e0y nu\u00f4i n\u00e0o th\u00ec khi t\u00ednh ra ch\u00fang ta \u0111\u1ec1u l\u1eddi 300.000 vn\u0111 nh\u00e9 c\u00e1c b\u1ea1n. C\u00e1c b\u1ea1n c\u00f3 th\u1ec3 t\u00ednh to\u00e1n v\u00e0o ti\u1ec1n \u00edt h\u01a1n ho\u1eb7c nhi\u1ec1u h\u01a1n t\u00f9y theo s\u1ed1 v\u1ed1n c\u1ee7a c\u00e1c b\u1ea1n nh\u00e9.<\/p>\n
Theo nh\u01b0 s\u1ed1 ti\u1ec1n ch\u01a1i trong 3 ng\u00e0y nh\u01b0 tr\u00ean th\u00ec c\u00e1c b\u1ea1n c\u1ea7n chu\u1ea9n b\u1ecb s\u1ed1 v\u1ed1n l\u00e0 360.000 vn\u0111 + 1.080.000 vn\u0111 +2.520.000 vn\u0111 = 2.980.000 vn\u0111.<\/p>\n